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GRADE 10 · Science · LEARNING COMPANION

Chemical Reactions and Equations — Exchange, Energy and Redox

Three guided lessons with explanations, visual steps, practice and a final check.

Original learning companion for selected Chemical Reactions and Equations outcomes. The two parts cover introductory theory through paper models and supplied observations. This is partial chapter coverage: it does not replace the full NCERT text, all exercises, laboratory practicals, teacher assessment or all transfer tasks. No home chemical experiment is assigned.

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LESSON 1

Explain displacement and precipitation

Use a supplied reactivity order and recognise an insoluble product in a double-displacement reaction.

A reaction can rearrange atoms or ions while preserving each element count.

  1. Use the supplied order

    For this exercise, use Mg > Zn > Cu: magnesium is more reactive than zinc, and zinc more reactive than copper. The order is evidence provided with the task, not something inferred from colour.

  2. Follow a displacement

    Mg + CuSO₄ → MgSO₄ + Cu shows magnesium replacing copper in the compound. In the same model, copper cannot displace magnesium from MgSO₄ because it is less reactive. This is a prediction exercise, not a mixing activity.

  3. Track the exchanged ions

    In CaCl₂(aq) + Na₂CO₃(aq) → CaCO₃(s) + 2NaCl(aq), calcium ions combine with carbonate ions. Sodium and chloride ions remain dissolved. The 2 before NaCl balances two Na and two Cl atoms.

  4. Identify the insoluble product

    CaCO₃(s) is the precipitate because calcium carbonate is insoluble under the stated aqueous conditions. Double displacement describes ion exchange; precipitation additionally identifies formation of an insoluble solid. Not every double-displacement example needs to produce a visible precipitate.

Worked example: Given Mg > Zn > Cu, predict Zn + CuSO₄ and Cu + ZnSO₄. Zinc is above copper, so Zn + CuSO₄ → ZnSO₄ + Cu is predicted. Copper is below zinc, so no displacement is predicted for Cu + ZnSO₄ in this model. Each decision follows the supplied order.

Watch for this: An aqueous label means dissolved, not “liquid precipitate”. A precipitate is the new insoluble solid; it is not the entire solution.

Discuss: Make paper cards labelled Ca²⁺, CO₃²⁻, Na⁺ and Cl⁻. Pair Ca²⁺ with CO₃²⁻ in a “solid” box and leave two Na⁺ and two Cl⁻ in a “solution” box. Check both atom counts and charge balance. Do not handle laboratory reagents.

LESSON 2

Reason about energy transfer

Distinguish exothermic from endothermic change and judge temperature evidence with stated conditions.

Temperature is a measurement; energy transfer describes movement of energy between system and surroundings.

  1. Choose a boundary

    Call the reacting materials the system. The container, nearby air and the rest of the environment belong to surroundings, depending on the boundary chosen. Say which boundary is used before drawing an energy arrow.

  2. Follow energy leaving

    For an exothermic reaction, draw an energy arrow from system to surroundings. Surroundings may warm if other transfers do not hide the effect. A flame or heater used to start a reaction does not by itself tell whether the reaction overall releases energy.

  3. Follow energy entering

    For an endothermic reaction, draw the arrow into the system. Energy must be taken in overall. Light or electrical input may supply energy, so temperature alone is not the entire description. Pattern labels such as decomposition remain a separate classification.

  4. Use temperature data carefully

    A supplied record starts at 20 °C and rises to 28 °C with no external heater and comparable surroundings. The 8 °C rise supports energy release by the change. It is supporting evidence under these conditions, not a universal rule that all warming observations prove chemical reaction.

Worked example: Two teacher-provided records use comparable containers and surroundings with no heater. Record P changes 24 °C → 30 °C; record Q changes 24 °C → 19 °C. P rises 6 °C, supporting energy release. Q falls 5 °C, supporting energy absorption. These observations need the supplied context; they do not alone establish the chemical identities or exact energy in joules.

Watch for this: “Needs ignition” does not mean “endothermic overall”. Starting energy and the total energy change describe different things.

Discuss: On paper, draw the system boundary and an energy arrow for each supplied data card. Add one possible interfering factor, such as an external heater or heat exchange with room air. This is data interpretation, not a chemical experiment.

LESSON 3

Connect oxidation, reduction and everyday effects

Track oxygen transfer and explain how exposure affects corrosion and rancidity.

A reaction can change how an element is combined without changing the element into another one.

  1. Track oxygen between substances

    Use the supplied equation CuO + CO → Cu + CO₂ as a paper model. Copper oxide loses oxygen while carbon monoxide gains it. The element counts remain Cu: 1, C: 1 and O: 2 on each side. Carbon monoxide is poisonous; this equation must not become a home activity.

  2. Name the paired changes

    CuO is reduced to Cu because it loses oxygen. CO is oxidised to CO₂ because it gains oxygen. In this example oxidation and reduction occur together. The oxygen/hydrogen definitions used here are a school-level model; not every redox reaction contains oxygen.

  3. Explain corrosion prevention

    Rusting of iron requires both oxygen and moisture in the usual classroom model. An intact coating can limit contact with them. If the coating is scratched, exposed iron may rust; a barrier reduces exposure rather than making iron permanently unreactive.

  4. Explain rancidity and its limits

    Oxidation can spoil fats and oils. Suitable airtight storage, lower temperature and protection from light can slow relevant changes, depending on the food. Such storage does not reverse spoilage or guarantee safety. Use a supplied storage record; do not taste or deliberately grow spoiled food.

Worked example: In a paper reaction model, Fe₂O₃ + 3CO → 2Fe + 3CO₂. Fe₂O₃ loses oxygen and is reduced; CO gains oxygen and is oxidised. Check Fe: 2 = 2, C: 3 = 3, O: 3 + 3 = 6 on the left and 3 × 2 = 6 on the right. Both changes belong to the same balanced reaction.

Watch for this: Oxidation does not mean “any change involving oxygen somewhere”. Identify which substance gains oxygen or loses hydrogen, and what happens to its reaction partner.

Discuss: Given a teacher’s photo or written record of a painted iron item with rust at a scratch, explain the exposed-surface mechanism. For food, compare only supplied packaging/storage data; never taste unknown or spoiled samples.

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Chemical Reactions and Equations — Evidence, Balancing and Patterns

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Chemical reactions · chapter pathway →

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Sources and coverage

Original learning companion for selected Chemical Reactions and Equations outcomes. The two parts cover introductory theory through paper models and supplied observations. This is partial chapter coverage: it does not replace the full NCERT text, all exercises, laboratory practicals, teacher assessment or all transfer tasks. No home chemical experiment is assigned.

Original HelioLearn teaching and questions. Source-aligned companion; not an official NCERT/CBSE publication or full textbook solution bank. Independent teacher review and narrated video are pending.